‘American Idol’ 2019 winner Laine Hardy diagnosed with coronavirus
{{#rendered}} {{/rendered}}Laine Hardy, the old soul with a modern twist who took home the title of “American Idol” in 2019, revealed that he has been diagnosed with coronavirus.
The 19-year-old Livingston, La., native made the statement in a Facebook post on Sunday and described his symptoms as “mild.”
“This wasn’t what I expected on the first day of summer," he wrote in the note, which was also shared on his Instagram Story.
{{#rendered}} {{/rendered}}‘AMERICAN IDOL’ ALUM GABBY BARRETT SAYS DEBUT ALBUM ‘GOLDMINE’ IS A NOD TO YEARS OF ‘HARD WORK’
He continued: “My doctor confirmed I have Coronavirus, but my symptoms are mild and I’m home recovering in quarantine. Y’all stay safe & healthy!”
Hardy had performed Friday, singing the national anthem at swearing-in ceremonies for Livingston Parish Sheriff Jason Ard’s third term, The Advocate reported.
{{#rendered}} {{/rendered}}CARRIE UNDERWOOD WON 'AMERICAN IDOL' 15 YEARS AGO: A LOOK BACK AT THE SINGER'S BIGGEST MOMENTS
Hardy also recently completed a virtual tour that was watched by more than 2 million viewers, and his next livestream is scheduled for Thursday evening.
'American Idol' Season 17 winner Laine Hardy performs during A Capitol Fourth on the West Lawn of the U.S. Capitol Building on July 04, 2019, in Washington, DC. (Photo by Paul Morigi/Getty Images for Capital Concerts, Inc.)
Acoustic versions of his new songs “Ground I Grew Up On” and “Let There Be Country” will debut on Friday.
{{#rendered}} {{/rendered}}CLICK HERE TO GET THE FOX NEWS APP
Hardy won the reality singing competition by beating Alejandro Aranda, who finished as runner-up, and Madison VanDenburg, who placed third.
The Associated Press contributed to this report.